What is the solution for dy=(y+3)/(x+4)dx ?

The solution for dy=(y+3)/(x+4)dx is y=e^{c_{1}}x+4e^{c_{1}}-3

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dy=(y+3)/(x+4)dx

d y = \frac{y + 3}{x + 4} d x

y = e^{c_{1}} x + 4 e^{c_{1}} - 3

Solution steps

d y = \frac{y + 3}{x + 4} d x

Solve separable ODE:

y = e^{c_{1}} x + 4 e^{c_{1}} - 3

y = e^{c_{1}} x + 4 e^{c_{1}} - 3

\frac{s d t}{d s} - 2 t = 0

\frac{d N}{d x} - 0.3 \cdot N - 32.4 = 0

\frac{d y}{d x} + 2 x y = x, y = \frac{1}{2} + \frac{1}{2} e^{- x^{2}}

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 1

\frac{d P}{d t} = 8 Pt, P (1) = 6

What is the solution for dy=(y+3)/(x+4)dx ?
The solution for dy=(y+3)/(x+4)dx is y=e^{c_{1}}x+4e^{c_{1}}-3