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Popular >

y^'-k^2y=0

Solution

y^{^{'}} - k^{2} y = 0

Solution

y = e^{k^{2} t + c_{1}}

Solution steps

y^{'} (t) - k^{2} y = 0

Solve separable ODE:

y = e^{k^{2} t + c_{1}}

y = e^{k^{2} t + c_{1}}

Graph

Popular Examples

y^'-2y^{1/3}=0,y(0)=0

y^{^{'}} - 2 y^{\frac{1}{3}} = 0, y (0) = 0

y^'-(7y)/(5160)=0.07

y^{^{'}} - \frac{7 y}{5160} = 0.07

(dy}{dx}=\frac{xcos(x))/y ,y(0)=-2

\frac{d y}{d x} = \frac{x cos ( x )}{y}, y (0) = - 2

e^yy^'=(((ln(t))^2))/t

e^{y} y^{^{'}} = \frac{( ( ln ( t ) ) ^{2} )}{t}

(dy)/(du)+3u^2y=5u^2

\frac{d y}{d u} + 3 u^{2} y = 5 u^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'-k^2y=0 ?
The solution for y^'-k^2y=0 is y=e^{k^2t+c_{1}}