What is the solution for y^'=-3x^2(y+2),y(1)=-1 ?

The solution for y^'=-3x^2(y+2),y(1)=-1 is y=e^{-x^3+1}-2

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y^'=-3x^2(y+2),y(1)=-1

y^{^{'}} = - 3 x^{2} (y + 2), y (1) = - 1

y = e^{- x^{3} + 1} - 2

Solution steps

y^{'} (x) = - 3 x^{2} (y + 2)

Solve separable ODE:

y = e^{- x^{3} + 1} - 2

y = e^{- x^{3} + 1} - 2

\frac{d y}{d x} = (1 + y)

\frac{d y}{d x} = 3 x y^{2} - 2 y^{2}

\frac{d p}{d t} = \frac{p - 900}{2}

220 = (0.5) (x) + (15.5) \frac{d x}{d t} + (20)

x^{3} y^{^{'}} = y^{2} (x - 4)

What is the solution for y^'=-3x^2(y+2),y(1)=-1 ?
The solution for y^'=-3x^2(y+2),y(1)=-1 is y=e^{-x^3+1}-2