What is the solution for y^'=0.1*y*(1-y/(80)) ?

The solution for y^'=0.1*y*(1-y/(80)) is y=-(80e^{0.1t+c_{1}})/(1-e^{0.1t+c_{1)}}

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y^'=0.1y(1-y/(80))

y^{^{'}} = 0.1 \cdot y \cdot (1 - \frac{y}{80})

y = - \frac{80 e ^{0.1 t + c_{1}}}{1 - e ^{0.1 t + c_{1}}}

Solution steps

y^{'} (t) = 0.1 \cdot y \cdot (1 - \frac{y}{80})

Solve separable ODE:

y = - \frac{80 e ^{0.1 t + c_{1}}}{1 - e ^{0.1 t + c_{1}}}

y = - \frac{80 e ^{0.1 t + c_{1}}}{1 - e ^{0.1 t + c_{1}}}

5 \frac{d v}{d t} = - 2 v^{2}

y^{^{'}} = 3 x 2 y

\frac{d}{d x} (f (x)^{- 1}) f (x) = \frac{1}{5} x + 5, x = 6

x \frac{d y}{d x} = x^{2} y^{2}

\frac{d y}{d x} = y^{2} \cdot x^{3}

What is the solution for y^'=0.1*y*(1-y/(80)) ?
The solution for y^'=0.1*y*(1-y/(80)) is y=-(80e^{0.1t+c_{1}})/(1-e^{0.1t+c_{1)}}