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Popular >

y^'=y*ln(y)

Solution

y^{^{'}} = y \cdot ln (y)

Solution

y = e^{e^{t + c_{1}}}

Solution steps

y^{'} (t) = y \cdot ln (y)

Solve separable ODE:

y = e^{e^{t + c_{1}}}

y = e^{e^{t + c_{1}}}

Graph

Popular Examples

x^{^{'}} = - 2 - x

dy=(y/x-cos(e)c^2 y/x)dx

d y = (\frac{y}{x} - cos (e) c^{2} \frac{y}{x}) d x

2xe^{x^2+y^2}+2ye^{x^2+y^2}(dy)/(dx)=0

2 x e^{x^{2} + y^{2}} + 2 y e^{x^{2} + y^{2}} \frac{d y}{d x} = 0

y^{^{'}} + 4 t y = - 2 t

xy^'-y=4x^9y,y(1)=10

x y^{^{'}} - y = 4 x^{9} y, y (1) = 10

Frequently Asked Questions (FAQ)

What is the solution for y^'=y*ln(y) ?
The solution for y^'=y*ln(y) is y=e^{e^{t+c_{1}}}