What is the solution for 2xe^{x^2+y^2}+2ye^{x^2+y^2}(dy)/(dx)=0 ?

The solution for 2xe^{x^2+y^2}+2ye^{x^2+y^2}(dy)/(dx)=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2xe^{x^2+y^2}+2ye^{x^2+y^2}(dy)/(dx)=0

2 x e^{x^{2} + y^{2}} + 2 y e^{x^{2} + y^{2}} \frac{d y}{d x} = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

2 x e^{x^{2} + y^{2}} + 2 y e^{x^{2} + y^{2}} \frac{d y}{d x} = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y^{^{'}} + 4 t y = - 2 t

x y^{^{'}} - y = 4 x^{9} y, y (1) = 10

y^{^{'}} = \frac{x ^{2} - 7}{y ^{2}}, y (0) = 4

x^{^{'}} = \frac{1}{x ^{3} - x}, x (0) = - 2

\frac{d y}{d x} = y^{4} cos (x)

What is the solution for 2xe^{x^2+y^2}+2ye^{x^2+y^2}(dy)/(dx)=0 ?
The solution for 2xe^{x^2+y^2}+2ye^{x^2+y^2}(dy)/(dx)=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}