What is the solution for (dy)/(dx)=-2cos(x)sin(y) ?

The solution for (dy)/(dx)=-2cos(x)sin(y) is y=2arctan(e^{-2sin(x)+c_{1}})+2pin

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(dy)/(dx)=-2cos(x)sin(y)

\frac{d y}{d x} = - 2 cos (x) sin (y)

y = 2 arctan (e^{- 2 s i n (x) + c_{1}}) + 2 πn

Solution steps

\frac{d y}{d x} = - 2 cos (x) sin (y)

Solve separable ODE:

y = 2 arctan (e^{- 2 s i n (x) + c_{1}}) + 2 πn

y = 2 arctan (e^{- 2 s i n (x) + c_{1}}) + 2 πn

\frac{d y}{d x} = \frac{x - 1}{y ^{2}}

y^{^{'}} \cdot ln (y) = y

x = \frac{y}{y ^{^{'}} + y}

20 (\frac{d v}{d t}) = - (20) (32) - 0.0025 v

\frac{d y}{d x} \cdot (1 + e^{x}) = e^{x - y}

What is the solution for (dy)/(dx)=-2cos(x)sin(y) ?
The solution for (dy)/(dx)=-2cos(x)sin(y) is y=2arctan(e^{-2sin(x)+c_{1}})+2pin