What is the solution for dy=θ^3dθ ?

The solution for dy=θ^3dθ is θ(y)=\sqrt[4]{4y+c_{1}},θ(y)=-\sqrt[4]{4y+c_{1}}

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dy=θ^3dθ

d y = θ^{3} d θ

θ (y) = 4 4 y + c_{1}, θ (y) = - 4 4 y + c_{1}

Solution steps

d y = θ^{3} d θ

Solve separable ODE:

θ (y) = 4 4 y + c_{1}, θ (y) = - 4 4 y + c_{1}

θ (y) = 4 4 y + c_{1}, θ (y) = - 4 4 y + c_{1}

\frac{d y}{d x} y = \frac{( 5 x ^{2} + 2 ) ( 3 x + 9 )}{8 x - 9}

(1 - x^{2}) y^{^{'}} = 6 x y, y (0) = 3

3 e^{2 x} \frac{d y}{d x} = - 4 \cdot \frac{x}{y ^{2}}

\frac{d y}{d x} = \frac{( 1 - y )}{xv}

y^{^{'}} = 1 - \frac{y}{10}

What is the solution for dy=θ^3dθ ?
The solution for dy=θ^3dθ is θ(y)=\sqrt[4]{4y+c_{1}},θ(y)=-\sqrt[4]{4y+c_{1}}