What is the derivative of (x^3/4-3x) ?

The derivative of (x^3/4-3x) is (3x^2)/4-3

What is the first derivative of (x^3/4-3x) ?

The first derivative of (x^3/4-3x) is (3x^2)/4-3

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Popular >

\frac{d}{d x} (\frac{x ^{3}}{4} - 3 x)

\frac{3 x ^{2}}{4} - 3

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{4} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{4}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (\frac{x ^{3}}{4}) = \frac{3 x ^{2}}{4}

\frac{d}{d x} (3 x) = 3

= \frac{3 x ^{2}}{4} - 3

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{1}{4 x})

\int \frac{1}{( x - 3 ) ( x - 2 )} d x

\int arcsin (t) d t

\frac{\partial}{\partial x} (2 x^{2} - 5 y^{2})

\int_{- 2}^{6} 4 x - x^{2} + 12 d x

What is the derivative of (x^3/4-3x) ?
The derivative of (x^3/4-3x) is (3x^2)/4-3
What is the first derivative of (x^3/4-3x) ?
The first derivative of (x^3/4-3x) is (3x^2)/4-3