What is the derivative of f(x)= 1/(x-3) ?

The derivative of f(x)= 1/(x-3) is -1/((x-3)^2)

What is the first derivative of f(x)= 1/(x-3) ?

The first derivative of f(x)= 1/(x-3) is -1/((x-3)^2)

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derivative of

f (x) = \frac{1}{x - 3}

- \frac{1}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

= - \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= - \frac{1}{( x - 3 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x - 3 ) ^{2}}

\int \frac{( x + 6 )}{x ^{2} + 9} d x

\frac{s + 1}{s ^{2} - 3 s + 2}

\frac{\partial}{\partial x} (9 x + y + 7 x y)

f^{^{'}} (x) = 1 - 2 x

x \to \infty lim (x^{2} + 5 x)

What is the derivative of f(x)= 1/(x-3) ?
The derivative of f(x)= 1/(x-3) is -1/((x-3)^2)
What is the first derivative of f(x)= 1/(x-3) ?
The first derivative of f(x)= 1/(x-3) is -1/((x-3)^2)