What is derivative of f(x)=-1/3 t^3+64t+3000 ?

The answer to derivative of f(x)=-1/3 t^3+64t+3000 is (dt)/(dx)=0

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derivative of f(x)=-1/3 t^3+64t+3000

derivative of

f (x) = - \frac{1}{3} t^{3} + 64 t + 3000

\frac{d t}{d x} = 0

Solution steps

f (x) = - \frac{1}{3} t^{3} + 64 t + 3000

Treat

t

t (x)

Differentiate both sides:

0 = 64 \frac{d t}{d x} - t^{2} \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

y^{^{'}} = \frac{1 - y ^{2}}{y}

\int \frac{( x - 7 )}{x ^{2} - 18 x + 82} d x

x^{2} + 25

\frac{1 + e ^{x}}{1 - e ^{x}}

\frac{d}{d x} ((\frac{x + 5}{x - 5})^{5})

What is derivative of f(x)=-1/3 t^3+64t+3000 ?
The answer to derivative of f(x)=-1/3 t^3+64t+3000 is (dt)/(dx)=0