What is the limit as x approaches 0+of 1-1/x ?

The limit as x approaches 0+of 1-1/x is -infinity

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limit as x approaches 0+of 1-1/x

x \to 0 + lim (1 - \frac{1}{x})

- \infty

Solution steps

x \to 0 + lim (1 - \frac{1}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (1) - x \to 0 + lim (\frac{1}{x})

x \to 0 + lim (1) = 1

x \to 0 + lim (\frac{1}{x}) = \infty

= 1 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

\frac{d y}{d x}, x^{3} - 3 x^{2} y + 2 x y^{2} = 12

x^{2} (1 - 6 x)

\frac{x}{( x ^{2} + 5 x + 6 )}, 0, 1

\int e^{- θ x} d x

\frac{d}{d x} (x + y - z)

What is the limit as x approaches 0+of 1-1/x ?
The limit as x approaches 0+of 1-1/x is -infinity