What is the derivative of sqrt(x^2+6) ?

The derivative of sqrt(x^2+6) is x/(sqrt(x^2+6))

What is the first derivative of sqrt(x^2+6) ?

The first derivative of sqrt(x^2+6) is x/(sqrt(x^2+6))

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derivative of

x^{2} + 6

\frac{x}{x ^{2} + 6}

Solution steps

\frac{d}{d x} (x^{2} + 6)

Apply the chain rule:

\frac{1}{2 x ^{2} + 6} \frac{d}{d x} (x^{2} + 6)

= \frac{1}{2 x ^{2} + 6} \frac{d}{d x} (x^{2} + 6)

\frac{d}{d x} (x^{2} + 6) = 2 x

= \frac{1}{2 x ^{2} + 6} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} + 6} \cdot 2 x : \frac{x}{x ^{2} + 6}

= \frac{x}{x ^{2} + 6}

arcsin (\frac{x}{7})

y^{^{'}} = \frac{x ^{2} + 2 \cdot y ^{2}}{x \cdot y}

\frac{d}{d x} (10 x sin (x))

9 x^{2} y^{2} + x^{\frac{3}{2}} y^{^{'}} = y^{2}

(x^{2} - 18) (2 x + 3)

What is the derivative of sqrt(x^2+6) ?
The derivative of sqrt(x^2+6) is x/(sqrt(x^2+6))
What is the first derivative of sqrt(x^2+6) ?
The first derivative of sqrt(x^2+6) is x/(sqrt(x^2+6))