What is (\partial)/(\partial x)(3sin(2x)) ?

The answer to (\partial)/(\partial x)(3sin(2x)) is 6cos(2x)

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(\partial)/(\partial x)(3sin(2x))

\frac{\partial}{\partial x} (3 sin (2 x))

6 cos (2 x)

Solution steps

\frac{\partial}{\partial x} (3 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= 3 cos (2 x) \cdot 2

Simplify

= 6 cos (2 x)

\int \frac{1}{3 - x} d x

\frac{\partial}{\partial y} (2 y^{3} - 3 y^{2} - 12 y + 6)

(x^{2} + 1) y^{^{'}} + 8 x (y - 1) = 0, y (0) = 4

\int x e^{\frac{- x}{2}} d x

\int_{0}^{1} 8 ln (x) d x

What is (\partial)/(\partial x)(3sin(2x)) ?
The answer to (\partial)/(\partial x)(3sin(2x)) is 6cos(2x)