What is the limit as x approaches 0+of ln(x^2) ?

The limit as x approaches 0+of ln(x^2) is -infinity

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limit as x approaches 0+of ln(x^2)

x \to 0 + lim (ln (x^{2}))

- \infty

Solution steps

x \to 0 + lim (ln (x^{2}))

ln (x^{2}) = 2 ln (x)

= x \to 0 + lim (2 ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to 0 + lim (ln (x))

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= 2 (- \infty)

Apply Infinity Property:

c \cdot (- \infty) = - \infty

= - \infty

\frac{d}{d x} (a x^{2} + b y (x)^{2})

\int (x^{3} + 2 x - 1) d x

a^{3} + cos^{3} (x)

y = ∣ 5 x ∣, y = x^{2} - 6

\frac{d}{d x} (ln (1 - 2 x))

What is the limit as x approaches 0+of ln(x^2) ?
The limit as x approaches 0+of ln(x^2) is -infinity