What is the derivative of ((8x^2/(4-x))^3) ?

The derivative of ((8x^2/(4-x))^3) is (1536x^4(8x-x^2))/((4-x)^4)

What is the first derivative of ((8x^2/(4-x))^3) ?

The first derivative of ((8x^2/(4-x))^3) is (1536x^4(8x-x^2))/((4-x)^4)

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\frac{d}{d x} ((\frac{8 x ^{2}}{4 - x})^{3})

\frac{1536 x ^{4} ( 8 x - x ^{2} )}{( 4 - x ) ^{4}}

Solution steps

\frac{d}{d x} ((\frac{8 x ^{2}}{4 - x})^{3})

Apply the chain rule:

3 (\frac{8 x ^{2}}{4 - x})^{2} \frac{d}{d x} (\frac{8 x ^{2}}{4 - x})

= 3 (\frac{8 x ^{2}}{4 - x})^{2} \frac{d}{d x} (\frac{8 x ^{2}}{4 - x})

\frac{d}{d x} (\frac{8 x ^{2}}{4 - x}) = \frac{8 ( 8 x - x ^{2} )}{( 4 - x ) ^{2}}

= 3 (\frac{8 x ^{2}}{4 - x})^{2} \frac{8 ( 8 x - x ^{2} )}{( 4 - x ) ^{2}}

Simplify

3 (\frac{8 x ^{2}}{4 - x})^{2} \frac{8 ( 8 x - x ^{2} )}{( 4 - x ) ^{2}} : \frac{1536 x ^{4} ( 8 x - x ^{2} )}{( 4 - x ) ^{4}}

= \frac{1536 x ^{4} ( 8 x - x ^{2} )}{( 4 - x ) ^{4}}

\int csc^{2} (x) cot (x) d x

\frac{d}{d x} (2 x cos (2 x))

\frac{d}{d x} (4 x^{3} + 3 x^{2} - 6 x)

y - x \frac{d y}{d x} = a (1 + x^{2} \frac{d y}{d x})

f (x) = (5 x - 9) (x + 5), (2, 7)

What is the derivative of ((8x^2/(4-x))^3) ?
The derivative of ((8x^2/(4-x))^3) is (1536x^4(8x-x^2))/((4-x)^4)
What is the first derivative of ((8x^2/(4-x))^3) ?
The first derivative of ((8x^2/(4-x))^3) is (1536x^4(8x-x^2))/((4-x)^4)