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Popular >

1+xy=xy^'

Solution

1 + x y = x y^{^{'}}

Solution

y = Ei (- x) e^{x} + c_{1} e^{x}

Solution steps

1 + x y = x y^{'} (x)

Solve linear ODE:

y = Ei (- x) e^{x} + c_{1} e^{x}

y = Ei (- x) e^{x} + c_{1} e^{x}

Popular Examples

Find the Antiderivative f(x)=5x-6 integral

f (x) = 5 x - 6

Using L'Hospital's Rule limit as x approaches 0 of (e^(5x)-1-5x)/(x^2)lhopital

x \to 0 lim (\frac{( e ^{5 x} - 1 - 5 x )}{( x ^{2} )})

Find the Derivative - d/dx y=4/x

- \frac{d}{d x} y = \frac{4}{x}

Find the Derivative - d/dx 1/x

- \frac{d}{d x} (\frac{1}{x})

Find the Derivative - d/dx y=3x

- \frac{d}{d x} y = 3 x

Frequently Asked Questions (FAQ)

What is the solution for 1+xy=xy^' ?
The solution for 1+xy=xy^' is y=\Ei(-x)e^x+c_{1}e^x