What is the derivative of t^3-12t^2+36t ?

The derivative of t^3-12t^2+36t is 3t^2-24t+36

What is the first derivative of t^3-12t^2+36t ?

The first derivative of t^3-12t^2+36t is 3t^2-24t+36

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derivative of

t^{3} - 12 t^{2} + 36 t

3 t^{2} - 24 t + 36

Solution steps

\frac{d}{d t} (t^{3} - 12 t^{2} + 36 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (12 t^{2}) + \frac{d}{d t} (36 t)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (12 t^{2}) = 24 t

\frac{d}{d t} (36 t) = 36

= 3 t^{2} - 24 t + 36

\frac{\partial}{\partial x} (cos (b x + c) e^{x y} x)

18 cos (x) + 9 sin^{2} (x)

\int - cos (u) d u

\frac{\partial}{\partial x} (ln (5 x^{2} + y^{2} + 9))

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 6 y = 0

What is the derivative of t^3-12t^2+36t ?
The derivative of t^3-12t^2+36t is 3t^2-24t+36
What is the first derivative of t^3-12t^2+36t ?
The first derivative of t^3-12t^2+36t is 3t^2-24t+36