What is the derivative of f(x)=8e^{-x}+e^{3x} ?

The derivative of f(x)=8e^{-x}+e^{3x} is -8e^{-x}+e^{3x}*3

What is the first derivative of f(x)=8e^{-x}+e^{3x} ?

The first derivative of f(x)=8e^{-x}+e^{3x} is -8e^{-x}+e^{3x}*3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 8 e^{- x} + e^{3 x}

- 8 e^{- x} + e^{3 x} \cdot 3

Solution steps

\frac{d}{d x} (8 e^{- x} + e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 e^{- x}) + \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (8 e^{- x}) = - 8 e^{- x}

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= - 8 e^{- x} + e^{3 x} \cdot 3

\frac{s + 1}{s ^{2}}

f (x) = 1 x^{3}

\frac{d}{d x} (8 sin (\frac{2 π}{3}))

\int \frac{2 x}{3 x - 5} d x

n = 1 \sum \infty \frac{n + 2}{n + 1}

What is the derivative of f(x)=8e^{-x}+e^{3x} ?
The derivative of f(x)=8e^{-x}+e^{3x} is -8e^{-x}+e^{3x}*3
What is the first derivative of f(x)=8e^{-x}+e^{3x} ?
The first derivative of f(x)=8e^{-x}+e^{3x} is -8e^{-x}+e^{3x}*3