What is the derivative of (x^3)/3-(x^2)/2-2x ?

The derivative of (x^3)/3-(x^2)/2-2x is x^2-x-2

What is the first derivative of (x^3)/3-(x^2)/2-2x ?

The first derivative of (x^3)/3-(x^2)/2-2x is x^2-x-2

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derivative of

\frac{x ^{3}}{3} - \frac{x ^{2}}{2} - 2 x

x^{2} - x - 2

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{x ^{2}}{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (\frac{x ^{2}}{2}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

\frac{d}{d x} (2 x) = 2

= x^{2} - x - 2

\frac{d}{d x} (e^{3 x} - 1)

\int_{2}^{4} \frac{x + y}{55} d y

\int \frac{x ( x - 8 )}{( x - 4 ) ^{3}} d x

2 (2 x^{2} + y^{2}) d x - x y d y = 0

f (x) = \frac{x - 5}{x + 3}

What is the derivative of (x^3)/3-(x^2)/2-2x ?
The derivative of (x^3)/3-(x^2)/2-2x is x^2-x-2
What is the first derivative of (x^3)/3-(x^2)/2-2x ?
The first derivative of (x^3)/3-(x^2)/2-2x is x^2-x-2