What is the solution for (dy)/(dx)= y/(x^3+3x^2+2x) ?

The solution for (dy)/(dx)= y/(x^3+3x^2+2x) is y=(c_{1}sqrt(x)sqrt(x+2))/(x+1)

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(dy)/(dx)= y/(x^3+3x^2+2x)

\frac{d y}{d x} = \frac{y}{x ^{3} + 3 x ^{2} + 2 x}

y = \frac{c _{1} x x + 2}{x + 1}

Solution steps

\frac{d y}{d x} = \frac{y}{x ^{3} + 3 x ^{2} + 2 x}

Solve separable ODE:

y = \frac{c _{1} x x + 2}{x + 1}

y = \frac{c _{1} x x + 2}{x + 1}

f (x) = ln (1 + sin (\frac{4}{x ^{2}}))

y = sin (4 x) + sin^{2} (4 x), (0, 0)

3 y d x + 2 x d y = 0

\int_{0}^{\infty} e^{- 4 x} d x

f (x) = 2 x e^{2 x}

What is the solution for (dy)/(dx)= y/(x^3+3x^2+2x) ?
The solution for (dy)/(dx)= y/(x^3+3x^2+2x) is y=(c_{1}sqrt(x)sqrt(x+2))/(x+1)