What is the derivative of e^x-8/x ?

The derivative of e^x-8/x is e^x+8/(x^2)

What is the first derivative of e^x-8/x ?

The first derivative of e^x-8/x is e^x+8/(x^2)

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derivative of

e^{x} - \frac{8}{x}

e^{x} + \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (e^{x} - \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (\frac{8}{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= e^{x} - (- \frac{8}{x ^{2}})

Simplify

= e^{x} + \frac{8}{x ^{2}}

x^{4} + 1

\int \frac{1}{x ^{\frac{1}{3}}} d x

\frac{d}{d x} (ln (\frac{5}{x}))

y^{^{''}} + 2 y^{^{'}} - 3 y = 2 x - 17

\frac{1}{cos ( x )}

What is the derivative of e^x-8/x ?
The derivative of e^x-8/x is e^x+8/(x^2)
What is the first derivative of e^x-8/x ?
The first derivative of e^x-8/x is e^x+8/(x^2)