What is the tangent of y= 5/(sqrt(x-2)),(3,5) ?

The tangent of y= 5/(sqrt(x-2)),(3,5) is y=-5/2 x+25/2

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tangent of y= 5/(sqrt(x-2)),(3,5)

tangent of

y = \frac{5}{x - 2}, (3, 5)

y = - \frac{5}{2} x + \frac{25}{2}

Solution steps

Find the slope of

y = \frac{5}{x - 2} : \frac{d y}{d x} = - \frac{5}{2 ( x - 2 ) ^{\frac{3}{2}}}

Compute the slope of

y = \frac{5}{x - 2}

(3, 5) : m = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(3, 5) : y = - \frac{5}{2} x + \frac{25}{2}

y = - \frac{5}{2} x + \frac{25}{2}

\int_{0}^{1} \frac{x ^{2}}{( x + 1 ) ^{3}} d x

y^{^{'}} - \frac{1}{x} y = - \frac{y ^{2}}{x}

\int 10 m^{- 2.3} + 5 m^{3.6} d m

\int \frac{1}{u ^{2} - 1} d u

x \cdot 5 x^{2}

What is the tangent of y= 5/(sqrt(x-2)),(3,5) ?
The tangent of y= 5/(sqrt(x-2)),(3,5) is y=-5/2 x+25/2