What is (\partial)/(\partial y)(20-5xy-5x) ?

The answer to (\partial)/(\partial y)(20-5xy-5x) is -5x

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(\partial)/(\partial y)(20-5xy-5x)

\frac{\partial}{\partial y} (20 - 5 x y - 5 x)

- 5 x

Solution steps

\frac{\partial}{\partial y} (20 - 5 x y - 5 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (20) - \frac{\partial}{\partial y} (5 x y) - \frac{\partial}{\partial y} (5 x)

\frac{\partial}{\partial y} (20) = 0

\frac{\partial}{\partial y} (5 x y) = 5 x

\frac{\partial}{\partial y} (5 x) = 0

= 0 - 5 x - 0

Simplify

= - 5 x

\frac{d}{d x} (2 lo g_{e} (x))

lo g_{2} (x)

\int (\frac{1}{x ^{2} + 1}) d x

\int 4 x^{3} + e^{x} - 1 d x

x \to 2 lim (\frac{x + 2}{x ^{3} + 8})

What is (\partial)/(\partial y)(20-5xy-5x) ?
The answer to (\partial)/(\partial y)(20-5xy-5x) is -5x