What is the derivative of 2log_{e}(x) ?

The derivative of 2log_{e}(x) is 2/x

What is the first derivative of 2log_{e}(x) ?

The first derivative of 2log_{e}(x) is 2/x

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\frac{d}{d x} (2 lo g_{e} (x))

\frac{2}{x}

Solution steps

\frac{d}{d x} (2 lo g_{e} (x))

Simplify

2 lo g_{e} (x) : 2 ln (x)

= \frac{d}{d x} (2 ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 \cdot \frac{1}{x}

Simplify

2 \cdot \frac{1}{x} : \frac{2}{x}

= \frac{2}{x}

lo g_{2} (x)

\int (\frac{1}{x ^{2} + 1}) d x

\int 4 x^{3} + e^{x} - 1 d x

x \to 2 lim (\frac{x + 2}{x ^{3} + 8})

\int (\frac{2}{1 + x ^{2}}) d x

What is the derivative of 2log_{e}(x) ?
The derivative of 2log_{e}(x) is 2/x
What is the first derivative of 2log_{e}(x) ?
The first derivative of 2log_{e}(x) is 2/x