What is the sum from n=5 to infinity of e^{5-2n} ?

The sum from n=5 to infinity of e^{5-2n} is converges

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sum from n=5 to infinity of e^{5-2n}

n = 5 \sum \infty e^{5 - 2 n}

converges

Solution steps

n = 5 \sum \infty e^{5 - 2 n}

Apply Series Ratio Test:

converges

= converges

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What is the sum from n=5 to infinity of e^{5-2n} ?
The sum from n=5 to infinity of e^{5-2n} is converges