What is the integral of 6xln(x) ?

The integral of 6xln(x) is 6(1/2 x^2ln(x)-(x^2)/4)+C

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integral of 6xln(x)

\int 6 x ln (x) d x

6 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) + C

Solution steps

\int 6 x ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x ln (x) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x

= 6 (\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x)

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 6 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4})

Add a constant to the solution

= 6 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) + C

sin (t^{2})

\int t e^{- i 2 π f t} d t

\int_{0}^{π} cos (3 x) d x

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 7, y^{^{'}} (0) = 7

f (x) = (3 x - 4)

What is the integral of 6xln(x) ?
The integral of 6xln(x) is 6(1/2 x^2ln(x)-(x^2)/4)+C