What is (\partial)/(\partial y)(ln(x-7y)) ?

The answer to (\partial)/(\partial y)(ln(x-7y)) is -7/(x-7y)

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(\partial)/(\partial y)(ln(x-7y))

\frac{\partial}{\partial y} (ln (x - 7 y))

- \frac{7}{x - 7 y}

Solution steps

\frac{\partial}{\partial y} (ln (x - 7 y))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{x - 7 y} \frac{\partial}{\partial y} (x - 7 y)

= \frac{1}{x - 7 y} \frac{\partial}{\partial y} (x - 7 y)

\frac{\partial}{\partial y} (x - 7 y) = - 7

= \frac{1}{x - 7 y} (- 7)

Simplify

\frac{1}{x - 7 y} (- 7) : - \frac{7}{x - 7 y}

= - \frac{7}{x - 7 y}

\int \frac{1}{3 - 2 x} d x

\frac{d}{d x} (- \frac{14}{x ^{3}})

(11 + x^{2}) y^{^{'}} - 2 x y = 0

\int \frac{1}{8 x ^{2} - 16 x + 64} d x

\frac{\partial}{\partial t} (s e^{t})

What is (\partial)/(\partial y)(ln(x-7y)) ?
The answer to (\partial)/(\partial y)(ln(x-7y)) is -7/(x-7y)