What is (\partial)/(\partial x)(12y^2x^2-6yx) ?

The answer to (\partial)/(\partial x)(12y^2x^2-6yx) is 24y^2x-6y

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(\partial)/(\partial x)(12y^2x^2-6yx)

\frac{\partial}{\partial x} (12 y^{2} x^{2} - 6 y x)

24 y^{2} x - 6 y

Solution steps

\frac{\partial}{\partial x} (12 y^{2} x^{2} - 6 y x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (12 y^{2} x^{2}) - \frac{\partial}{\partial x} (6 y x)

\frac{\partial}{\partial x} (12 y^{2} x^{2}) = 24 y^{2} x

\frac{\partial}{\partial x} (6 y x) = 6 y

= 24 y^{2} x - 6 y

\frac{d}{d x} (sin^{4} (4 x))

\frac{d x}{d y} = 3 x (5 - x)

(3 t + 6 y + 3) = \frac{d y}{d t}

x

\int 1 - x d x

What is (\partial)/(\partial x)(12y^2x^2-6yx) ?
The answer to (\partial)/(\partial x)(12y^2x^2-6yx) is 24y^2x-6y