What is the tangent of-5x^2 ?

The tangent of-5x^2 is y=-10a_{0}x+5a_{0}^2

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tangent of-5x^2

tangent of

- 5 x^{2}

y = - 10 a_{0} x + 5 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 5 a_{0}^{2})

Find the slope of

y = - 5 x^{2} : \frac{d y}{d x} = - 10 x

Compute the slope of

y = - 5 x^{2}

x = a_{0} : m = - 10 a_{0}

Find the line with slope m=

- 10 a_{0}

and passing through

(a_{0}, - 5 a_{0}^{2}) : y = - 10 a_{0} x + 5 a_{0}^{2}

y = - 10 a_{0} x + 5 a_{0}^{2}

\frac{\partial}{\partial x} (\frac{( x ^{2} )}{y + 1})

\int \frac{y}{( y ^{2} - 1 ) ^{\frac{3}{2}}} d y

(ln (x + 1))^{^{'}}

x^{2} + 1, 0, 1

x \to \infty lim (1.0 1^{x})