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Popular >

y^'= 1/(x+y)

Solution

y^{^{'}} = \frac{1}{x + y}

Solution

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

Solution steps

y^{'} (x) = \frac{1}{x + y}

Solve exact ODE:

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

y = - W (\frac{c _{1}}{e ^{x + 1}}) - x - 1

Popular Examples

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integral of 1/(xsqrt(1-x^2))

\int \frac{1}{x 1 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/(x+y) ?
The solution for y^'= 1/(x+y) is y=-\W((c_{1})/(e^{x+1)})-x-1