What is the derivative of x^5-5x^3+4x ?

The derivative of x^5-5x^3+4x is 5x^4-15x^2+4

What is the first derivative of x^5-5x^3+4x ?

The first derivative of x^5-5x^3+4x is 5x^4-15x^2+4

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\frac{d}{d x} (x^{5} - 5 x^{3} + 4 x)

5 x^{4} - 15 x^{2} + 4

Solution steps

\frac{d}{d x} (x^{5} - 5 x^{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) - \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (4 x) = 4

= 5 x^{4} - 15 x^{2} + 4

e^{8 x^{2}}

\frac{d}{d x} ((2 x - x^{2})^{2} + 9)

\int (x - 2) ln (x) d x

4 x^{2} + y^{2} = 25, (2, 3)

70 x^{- 5}

What is the derivative of x^5-5x^3+4x ?
The derivative of x^5-5x^3+4x is 5x^4-15x^2+4
What is the first derivative of x^5-5x^3+4x ?
The first derivative of x^5-5x^3+4x is 5x^4-15x^2+4