What is the tangent of f(x)= x/(x+1),(-2,2) ?

The tangent of f(x)= x/(x+1),(-2,2) is y=x+4

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tangent of f(x)= x/(x+1),(-2,2)

tangent of

f (x) = \frac{x}{x + 1}, (- 2, 2)

y = x + 4

Solution steps

Find the slope of

f (x) = \frac{x}{x + 1} : \frac{df ( x )}{d x} = \frac{1}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{x}{x + 1}

(- 2, 2) : m = 1

Find the line with slope m=

1

and passing through

(- 2, 2) : y = x + 4

y = x + 4

\int \frac{1}{x ^{2} + x} d x

f (x) = \frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7

\int_{0}^{\frac{π}{2}} cos (θ) d θ

\frac{\partial}{\partial x} (x y^{- 1})

\int \frac{1}{6 y ^{2}} d y

What is the tangent of f(x)= x/(x+1),(-2,2) ?
The tangent of f(x)= x/(x+1),(-2,2) is y=x+4