What is the integral of 4/(\sqrt[4]{x)} ?

The integral of 4/(\sqrt[4]{x)} is 16/3 x^{3/4}+C

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integral of 4/(\sqrt[4]{x)}

\frac{16}{3} x^{\frac{3}{4}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{4}{3} x^{\frac{3}{4}}

= 4 \cdot \frac{4}{3} x^{\frac{3}{4}}

Simplify

4 \cdot \frac{4}{3} x^{\frac{3}{4}} : \frac{16}{3} x^{\frac{3}{4}}

= \frac{16}{3} x^{\frac{3}{4}}

Add a constant to the solution

= \frac{16}{3} x^{\frac{3}{4}} + C

i = 1 \sum \infty (\frac{3}{2})^{i}

\int \frac{x}{x ^{2} + x} d x

\frac{d}{d x} (x^{2} \cdot e^{- x^{2}})

f (x) = - x^{2} - 2 x - 2, at x = - 3

What is the integral of 4/(\sqrt[4]{x)} ?
The integral of 4/(\sqrt[4]{x)} is 16/3 x^{3/4}+C