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Popular >

1/2 y^'+y=0

Solution

\frac{1}{2} y^{^{'}} + y = 0

Solution

y = e^{- 2 t + c_{1}}

Solution steps

\frac{1}{2} y^{'} (t) + y = 0

Solve separable ODE:

y = e^{- 2 t + c_{1}}

y = e^{- 2 t + c_{1}}

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Frequently Asked Questions (FAQ)

What is the solution for 1/2 y^'+y=0 ?
The solution for 1/2 y^'+y=0 is y=e^{-2t+c_{1}}