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Popular >

2y^'=y

Solution

2 y^{^{'}} = y

Solution

y = e^{\frac{t + c _{1}}{2}}

Solution steps

2 y^{'} (t) = y

Solve separable ODE:

y = e^{\frac{t + c _{1}}{2}}

y = e^{\frac{t + c _{1}}{2}}

Popular Examples

(\partial)/(\partial x)(4sin^2(x))

\frac{\partial}{\partial x} (4 sin^{2} (x))

tangent of f(x)= 2/x tangent of

f (x) = \frac{2}{x}

derivative of e^pi derivative of

e^{π}

(\partial)/(\partial y)(4x-2y)

\frac{\partial}{\partial y} (4 x - 2 y)

integral of 4+1/x

\int 4 + \frac{1}{x} d x

Frequently Asked Questions (FAQ)

What is the solution for 2y^'=y ?
The solution for 2y^'=y is y=e^{(t+c_{1})/2}