What is the integral of 2x^4sqrt(x^5+6) ?

The integral of 2x^4sqrt(x^5+6) is 4/15 (x^5+6)^{3/2}+C

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integral of 2x^4sqrt(x^5+6)

\int 2 x^{4} x^{5} + 6 d x

\frac{4}{15} (x^{5} + 6)^{\frac{3}{2}} + C

Solution steps

\int 2 x^{4} x^{5} + 6 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{4} x^{5} + 6 d x

Apply u-substitution

: \int \frac{u}{5} d u

= 2 \cdot \int \frac{u}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{5} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= 2 \cdot \frac{1}{5} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x^{5} + 6

= 2 \cdot \frac{1}{5} \cdot \frac{2}{3} (x^{5} + 6)^{\frac{3}{2}}

Simplify

2 \cdot \frac{1}{5} \cdot \frac{2}{3} (x^{5} + 6)^{\frac{3}{2}} : \frac{4}{15} (x^{5} + 6)^{\frac{3}{2}}

= \frac{4}{15} (x^{5} + 6)^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{15} (x^{5} + 6)^{\frac{3}{2}} + C

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What is the integral of 2x^4sqrt(x^5+6) ?
The integral of 2x^4sqrt(x^5+6) is 4/15 (x^5+6)^{3/2}+C