What is (\partial)/(\partial x)(2xcos(2y)-y^2) ?

The answer to (\partial)/(\partial x)(2xcos(2y)-y^2) is 2cos(2y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2xcos(2y)-y^2)

\frac{\partial}{\partial x} (2 x cos (2 y) - y^{2})

2 cos (2 y)

Solution steps

\frac{\partial}{\partial x} (2 x cos (2 y) - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x cos (2 y)) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (2 x cos (2 y)) = 2 cos (2 y)

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 cos (2 y) - 0

Simplify

= 2 cos (2 y)

\int \frac{2 x}{x + 1} d x

x \to 0 lim (\frac{g ( x )}{x})

\frac{d y}{d x} = x e^{x - 2 y}

\int_{1}^{2} (x^{3} + \frac{1}{4 x ^{3}}) d x

\frac{d y}{d x} - \frac{2}{3 x} y + \frac{x ^{2} + 2}{3} y^{4} = 0

What is (\partial)/(\partial x)(2xcos(2y)-y^2) ?
The answer to (\partial)/(\partial x)(2xcos(2y)-y^2) is 2cos(2y)