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Popular >

(4x^2)y^{''}+4xy^'=0

Solution

(4 x^{2}) y^{^{''}} + 4 x y^{^{'}} = 0

Solution

y = c_{1} + c_{2} ln (x)

Solution steps

(4 x^{2}) y^{''} (x) + 4 x y^{'} (x) = 0

Solve linear ODE:

y = c_{1} + c_{2} ln (x)

y = c_{1} + c_{2} ln (x)

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\int 9 x^{5} e^{x} d x

Frequently Asked Questions (FAQ)

What is the solution for (4x^2)y^{''}+4xy^'=0 ?
The solution for (4x^2)y^{''}+4xy^'=0 is y=c_{1}+c_{2}ln(x)