What is the derivative of 1/(4x-3) ?

The derivative of 1/(4x-3) is -4/((4x-3)^2)

What is the first derivative of 1/(4x-3) ?

The first derivative of 1/(4x-3) is -4/((4x-3)^2)

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derivative of

\frac{1}{4 x - 3}

- \frac{4}{( 4 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{4 x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((4 x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x - 3 ) ^{2}} \frac{d}{d x} (4 x - 3)

= - \frac{1}{( 4 x - 3 ) ^{2}} \frac{d}{d x} (4 x - 3)

\frac{d}{d x} (4 x - 3) = 4

= - \frac{1}{( 4 x - 3 ) ^{2}} \cdot 4

Simplify

- \frac{1}{( 4 x - 3 ) ^{2}} \cdot 4 : - \frac{4}{( 4 x - 3 ) ^{2}}

= - \frac{4}{( 4 x - 3 ) ^{2}}

\int_{0}^{1} 5 e^{- 3 x} d x

\int_{7}^{9} (x^{2} + 2 x - 4) d x

\frac{d r}{d θ} = 10 - 6 r

\int \frac{tan ( z )}{cos ^{2} ( z )} d z

x \to 1 + lim (\frac{4 x - 3}{x - 1})

What is the derivative of 1/(4x-3) ?
The derivative of 1/(4x-3) is -4/((4x-3)^2)
What is the first derivative of 1/(4x-3) ?
The first derivative of 1/(4x-3) is -4/((4x-3)^2)