What is the integral from-2 to 2 of |x^2+3x-4| ?

The integral from-2 to 2 of |x^2+3x-4| is 49/3

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integral from-2 to 2 of |x^2+3x-4|

\int_{- 2}^{2} x^{2} + 3 x - 4 d x

\frac{49}{3}

Decimal Notation

16.33333 \dots

Solution steps

\int_{- 2}^{2} x^{2} + 3 x - 4 d x

Eliminate Absolutes

= \int_{- 2}^{1} - x^{2} - 3 x + 4 d x + \int_{1}^{2} x^{2} + 3 x - 4 d x

\int_{- 2}^{1} - x^{2} - 3 x + 4 d x = \frac{27}{2}

\int_{1}^{2} x^{2} + 3 x - 4 d x = \frac{17}{6}

= \frac{27}{2} + \frac{17}{6}

Simplify

\frac{27}{2} + \frac{17}{6} : \frac{49}{3}

= \frac{49}{3}

y^{^{'}} - \frac{6}{x} y = \frac{y ^{4}}{x ^{7}}

\int 4 x^{3} (7 x^{4} + 12)^{3} d x

(6 x^{2} + 4 x)^{2}

\frac{\partial}{\partial y} (\frac{x - y}{x ^{2} + y ^{2}})

3 e^{t}

What is the integral from-2 to 2 of |x^2+3x-4| ?
The integral from-2 to 2 of |x^2+3x-4| is 49/3