What is the integral of (e^{2sqrt(t)})/(sqrt(t)) ?

The integral of (e^{2sqrt(t)})/(sqrt(t)) is e^{2sqrt(t)}+C

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integral of (e^{2sqrt(t)})/(sqrt(t))

\int \frac{e ^{2 t}}{t} d t

e^{2 t} + C

Solution steps

\int \frac{e ^{2 t}}{t} d t

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = 2 t

= e^{2 t}

Add a constant to the solution

= e^{2 t} + C

y = 5 ln (x), at x = 1

y^{^{''}} = 2 y

x^{2} - 5 x

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{1 + e}

\int 1 + x d x

What is the integral of (e^{2sqrt(t)})/(sqrt(t)) ?
The integral of (e^{2sqrt(t)})/(sqrt(t)) is e^{2sqrt(t)}+C