What is (\partial)/(\partial x)(10cos(x)y^2z) ?

The answer to (\partial)/(\partial x)(10cos(x)y^2z) is -10y^2zsin(x)

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(\partial)/(\partial x)(10cos(x)y^2z)

\frac{\partial}{\partial x} (10 cos (x) y^{2} z)

- 10 y^{2} z sin (x)

Solution steps

\frac{\partial}{\partial x} (10 cos (x) y^{2} z)

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 y^{2} z \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 10 y^{2} z (- sin (x))

Simplify

= - 10 y^{2} z sin (x)

3 x^{2} e^{x} + e^{x} (x^{3} + 6)

\frac{\partial}{\partial y} (9 e^{x} ln (y))

\frac{d}{d x} (\frac{5 x ^{2} - x ^{4}}{9})

n = 1 \sum \infty 1 + \frac{1}{n}

2^{70}

What is (\partial)/(\partial x)(10cos(x)y^2z) ?
The answer to (\partial)/(\partial x)(10cos(x)y^2z) is -10y^2zsin(x)