What is the integral of (tan(x))/(sec^2(x)) ?

The integral of (tan(x))/(sec^2(x)) is (sin^2(x))/2+C

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integral of (tan(x))/(sec^2(x))

\int \frac{tan ( x )}{sec ^{2} ( x )} d x

\frac{sin ^{2} ( x )}{2} + C

Solution steps

\int \frac{tan ( x )}{sec ^{2} ( x )} d x

Express with sin, cos

= \int cos (x) sin (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (x)

= \frac{sin ^{2} ( x )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( x )}{2} + C

\frac{2 x ^{5} + 7}{x ^{3}}

\frac{( x ^{2} )}{x - 7}

\frac{x}{x ^{4} + 1}

\frac{\partial}{\partial u} (4 u cos (v))

\int 2 x^{2} - 2 x^{- 1} d x

What is the integral of (tan(x))/(sec^2(x)) ?
The integral of (tan(x))/(sec^2(x)) is (sin^2(x))/2+C