What is the integral from 1 to 4 of 1/t ?

The integral from 1 to 4 of 1/t is 2ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 1/t

\int_{1}^{4} \frac{1}{t} d t

2 ln (2)

Decimal Notation

1.38629 \dots

Solution steps

\int_{1}^{4} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= [ln ∣ t ∣]_{1}^{4}

Compute the boundaries:

2 ln (2)

= 2 ln (2)

\frac{d}{d x} (\frac{2 x ^{3} - 16}{x - 2})

y = \frac{5 x}{x + 3}, (2, 2)

f (x) = (x - 6) (2 x + 1)

f (x) = 2 + cos (x), at x = \frac{π}{2}

\frac{d}{d x} (\frac{- 9}{x ^{2} + 81})

What is the integral from 1 to 4 of 1/t ?
The integral from 1 to 4 of 1/t is 2ln(2)