What is the integral from 1 to 3 of (x^2-5x+3) ?

The integral from 1 to 3 of (x^2-5x+3) is -16/3

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integral from 1 to 3 of (x^2-5x+3)

\int_{1}^{3} (x^{2} - 5 x + 3) d x

- \frac{16}{3}

Decimal

- 5.33333 \dots

Solution steps

\int_{1}^{3} x^{2} - 5 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x - \int_{1}^{3} 5 x d x + \int_{1}^{3} 3 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 5 x d x = 20

\int_{1}^{3} 3 d x = 6

= \frac{26}{3} - 20 + 6

Simplify

\frac{26}{3} - 20 + 6 : - \frac{16}{3}

= - \frac{16}{3}

- 1

\frac{d}{d x} (cos^{2} (e^{c o s^{2} (x)}))

\int ln (cos (x)) sin (x) d x

y^{^{'}} + \frac{2}{t} y = \frac{cos ( t )}{t ^{2}}

\int sin^{2} (3 x) \cdot cos^{4} (3 x) d x

What is the integral from 1 to 3 of (x^2-5x+3) ?
The integral from 1 to 3 of (x^2-5x+3) is -16/3