What is (\partial)/(\partial x)(x+ysin(t)) ?

The answer to (\partial)/(\partial x)(x+ysin(t)) is 1

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(\partial)/(\partial x)(x+ysin(t))

\frac{\partial}{\partial x} (x + y sin (t))

1

Solution steps

\frac{\partial}{\partial x} (x + y sin (t))

Treat

y, t

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y sin (t))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y sin (t)) = 0

= 1 + 0

Simplify

= 1

f (x) = - 7 x

x \to 0 - lim (\frac{∣ 3 x ∣}{x})

\frac{d}{d x} (x - 2 cos (x))

x \to 2 + lim (e^{\frac{1}{2 - x}})

- 6 x^{2} + 9 x + 4 x^{3}

What is (\partial)/(\partial x)(x+ysin(t)) ?
The answer to (\partial)/(\partial x)(x+ysin(t)) is 1