What is the derivative of y=4-2x-x^{-3} ?

The derivative of y=4-2x-x^{-3} is 3/(x^4)-2

What is the first derivative of y=4-2x-x^{-3} ?

The first derivative of y=4-2x-x^{-3} is 3/(x^4)-2

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derivative of

y = 4 - 2 x - x^{- 3}

\frac{3}{x ^{4}} - 2

Solution steps

\frac{d}{d x} (4 - 2 x - x^{- 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d}{d x} (2 x) - \frac{d}{d x} (x^{- 3})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x^{- 3}) = - \frac{3}{x ^{4}}

= 0 - 2 - (- \frac{3}{x ^{4}})

Simplify

= \frac{3}{x ^{4}} - 2

x \to - 2 lim (\frac{x - 2}{x + 2})

y^{^{'}} = \frac{x e ^{x^{2}}}{2}

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3})

\int r^{2} sec^{2} (r^{3}) d r

- 6 + 250 x^{3} - 3 x^{5}

What is the derivative of y=4-2x-x^{-3} ?
The derivative of y=4-2x-x^{-3} is 3/(x^4)-2
What is the first derivative of y=4-2x-x^{-3} ?
The first derivative of y=4-2x-x^{-3} is 3/(x^4)-2