What is the solution for y^'-4y=10sin(2t) ?

The solution for y^'-4y=10sin(2t) is y=-cos(2t)-2sin(2t)+c_{1}e^{4t}

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y^'-4y=10sin(2t)

y^{^{'}} - 4 y = 10 sin (2 t)

y = - cos (2 t) - 2 sin (2 t) + c_{1} e^{4 t}

Solution steps

y^{'} (t) - 4 y = 10 sin (2 t)

Solve linear ODE:

y = - cos (2 t) - 2 sin (2 t) + c_{1} e^{4 t}

y = - cos (2 t) - 2 sin (2 t) + c_{1} e^{4 t}

\int (\frac{2}{y + 1})^{2} d y

f (x) = x^{2} - 8, (- 2, - 4)

\frac{4}{( s ^{4} + 4 )}

\int_{2}^{\infty} x e^{- 9 x} d x

x \to 4 lim (4 - x)

What is the solution for y^'-4y=10sin(2t) ?
The solution for y^'-4y=10sin(2t) is y=-cos(2t)-2sin(2t)+c_{1}e^{4t}