What is the derivative of x^4-2 ?

The derivative of x^4-2 is 4x^3

What is the first derivative of x^4-2 ?

The first derivative of x^4-2 is 4x^3

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derivative of

x^{4} - 2

4 x^{3}

Solution steps

\frac{d}{d x} (x^{4} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2) = 0

= 4 x^{3} - 0

Simplify

= 4 x^{3}

- x^{2} + 9 x

\int 3 e^{- x} sin (x) d x

\frac{2 s - 4}{s ^{2} - 4 s + 13}

\frac{d}{d x} (- 0.5 x^{2} + 64 x - 25)

y^{^{''}} + y = 3 sin (x)